[tex] \: \displaystyle{\sf{\int\limits^2_1 {(4x+2)} \, dx = . \: \: . \: \: .}}[/tex]
di jwb -^-
Penjelasan dengan langkah-langkah:
[tex]\displaystyle{\sf{\int\limits^2_1 {(4x+2)} \, dx = . \: \: . \: \: .}}[/tex]
Kata org cari integral tak tentu dlu :
[tex] \sf = \frac{4}{1 + 1} {x}^{1 + 1} + \frac{2}{0 + 1} {x}^{0 + 1} [/tex]
[tex] \sf = \frac{4}{2} {x}^{2} + \frac{2}{1} x[/tex]
[tex] \sf = 2 {x}^{2} + 2x[/tex]
_______________
2x² + 2x
= [ 2, 1 ]
= 2(2²) + 2(2) - ( 2(1¹) + 2(1) )
= 2(4) + 4 - ( 2(1) + 2 )
= 8 + 4 - ( 2 + 2 )
= 8 + 4 - 4
= 12 - 4
= 8
Penjelasan dengan langkah-langkah:
[tex] \: \displaystyle{\sf{\int\limits^2_1 {(4x+2)} \, dx = . \: \: . \: \: .}}[/tex]
[tex] = \frac{4}{1 + 1} {x}^{1 + 1} + \frac{2}{0 + 1} {x}^{0 + 1} + c[/tex]
[tex] = \frac{4}{2} {x}^{2} + \frac{2}{1} {x}^{1} + c[/tex]
[tex] = \frac{ {4x}^{2} }{2} + \frac{ {2x}^{1} }{1} + c[/tex]
[tex] = {2x}^{2} + {2x}^{} + c[/tex]
------------
= 2x² + 2x
= 2(2²) + 2(2) - (2(1¹) + 2(1)
= 2(4) + 4 - (2 + 2)
= 8 + 4 - 4
= 12 - 4
= 8
